Novice - Problem 6, Solution in cpp

/*********************************** 
Paul Miller
Solution to Cube problem
***********************************/

#include <stdio.h>

#define DEBUG (1 == 1)

#define BLACK   7 // 111B
#define CLEAR   0 // 000B

#define RED     4 // 100B
#define GREEN   2 // 010B
#define BLUE    1 // 001B

#define BROWN   6 // 110B
#define AQUA    3 // 011B
#define PURPLE  5 // 101B


int main (void)
{
   int ncubes;
   int side[6];
   int s;
   int whichside;
   int otherside[6];

   otherside[0]=5;
   otherside[1]=4;
   otherside[2]=3;
   otherside[3]=2;
   otherside[4]=1;
   otherside[5]=0;


   scanf(" %d", &ncubes);
   if (DEBUG) printf("Number of cubes %d\n",ncubes);
   for (int l = 0; l < ncubes; l++)
   {
      scanf (" %d", &whichside);
      if (DEBUG) printf("Side to do: %d\n",whichside);
      whichside--;  // convert to subscript
      for (s=0; s<6; s++)
      {
         int tempside;
         scanf ("%d", &tempside);
         switch (tempside)
         {
            case 7:  // red
               side[s] = RED;
            break;

            case 9:  // green
               side[s] = GREEN;
            break;

            case 8:  // blue
               side[s] = BLUE;
            break;

            case 0:  // clear
               side[s] = CLEAR;
            break;

            case 3:  // black
               side[s] = BLACK;
            break;
         }
	if (DEBUG) printf("side: %d\tvalue: %d\tconverted: %d\n", s, tempside, side[s]); 
      }


      //* Now process...
      int col1 = side[whichside];
      int col2 = side[5-whichside];

      if (DEBUG) printf("side: %d(%d)\topposite: %d(%d)\n", whichside, col1, 5-whichside, col2); 

      if (!(col1 ^ BLACK) || !(col2 ^ BLACK))
         printf ("BLACK\n");

      else 
      {
         if (col1 & col2)
            printf ("DARK ");

         col1 |= col2;  // combine bits of both colors

         switch (col1)
         {
            case CLEAR:
               printf ("CLEAR\n");
            break;

            case RED:
               printf ("RED\n");
            break;

            case GREEN:
               printf ("GREEN\n");
            break;

            case BLUE:
               printf ("BLUE\n");
            break;

            case BROWN:
               printf ("BROWN\n");
            break;

            case AQUA:
               printf ("AQUA\n");
            break;

            case PURPLE:
               printf ("PURPLE\n");
            break;

         }
      }
   }  // end for() to read in cubes

   return  0;
}